What mass of potassium reacted with an excess of sulfuric acid if 3.48 g of potassium sulfate was formed as a result of the reaction?

univerkov | January 17, 2021 | education

Given:
m (K2SO4) = 3.48 g
To find:
m (K)
Decision:
2K + H2SO4 = K2SO4 + H2
n (K2SO4) = m / M = 3.48 g / 174 g / mol = 0.02 mol
n (K2SO4): n (K) = 1: 2
n (K) = 0.02 mol * 2 = 0.04 mol
m (K) = n * M = 0.04 mol * 39 g / mol = 1.56 g
Answer: 1.56 g

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