First of all, the mass of the potassium sulfate salt should be determined. To do this, you will need to use the following formula.
W = m r.v. / m r-ra * 100%.
In this formula, the following values were used: m r.v. is the mass of the soluble substance, m solution is the mass of the solution, W is the mass fraction of the salt solution.
m r.h. = m solution * W / 100%.
m salt = 250 * 15/100 = 37.5 g.
It turns out that the mass of the potassium sulfate salt in solution is 37.5 g.
Next, we determine the mass of water.
m solution = m H2O + m salt.
m H2O = m solution – m salt.
That is, in order to determine the mass of water, the mass of salt should be subtracted from the mass of the solution.
m H2O = 250 – 37.5 = 212.5 g.
Next, we determine the volume of water. To do this, use the following formula.
m = p * V.
Where m is the mass of the substance.
p is the density of the connection.
V is the volume of a given substance.
p = 1 g / ml.
V (H2O) = m / p.
V (H2O) = 212.5g / 1g / ml = 212.5ml.
As a result of the solution, a volume of water equal to 212.5 ml was obtained.
Answer: the mass of the potassium sulfate salt is 37.5 g; the volume of water required to prepare the solution is 212.5 g.