What mass of potassium sulfate is formed by the interaction of 49 g of sulfuric acid with potassium hydroxide?

| April 28, 2021 | education

Acids interact with alkalis to form salt and water. These reactions are called neutralization. When sulfuric acid interacts with potassium hydroxide, potassium sulfate and water are formed.

H2SO4 + 2KOH = K2SO4 + 2H2O.

Find the molecular weights of sulfuric acid and potassium sulfate
We find the molecular masses according to the periodic table, adding up the atomic masses of the elements.

M (H2SO4) = (1 x 2) + 32 + (16 x 4) = 2 + 32 + 64 = 98 g / mol.

M (K2SO4) = (39 x 2) + 32 + (16 x 4) = 79 + 32 + 64 = 174 g / mol.

Find the mass of potassium sulfate
The mass of potassium sulfate is determined by the following formula:

m (H2SO4): M (H2SO4) = m (K2SO4): M (K2SO4),

hence m (K2SO4) = (m (H2SO4) x M (K2SO4)): M (H2SO4).

Substitute the values:

m (K2SO4) = (49 g x 174 g / mol): 98 g / mol = 8526: 98 = 87 g.

Answer: m (K2SO4) = 87 g.



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