What mass of potassium sulfate is formed by the interaction of 49 g of sulfuric acid with potassium hydroxide?

univerkov | January 17, 2021 | education

Given:
m (H2SO4) = 49 g
To find:
m (K2SO4)
Decision:
2KOH + H2SO4 = K2SO4 + 2H2O
n (H2SO4) = m / M = 49 g / 98 g / mol = 0.5 mol
n (H2SO4): n (K2SO4) = 1: 1
n (K2SO4) = 0.5 mol
m (K2SO4) = n * M = 0.5 mol * 174 g / mol = 87 g
Answer: 87 g

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