What mass of precipitate is formed if an excess of barium chloride is added to a solution

What mass of precipitate is formed if an excess of barium chloride is added to a solution of sulfuric acid weighing 45 g., With a mass fraction of acid of 5%

When barium chloride solution is added to sulfuric acid, barium sulfate precipitates.
H2SO4 + BaCl2 = BaSO4 + 2HCl.
The mass of the acid in the solution is.
m (H2SO4) = m (solution) • W (H2SO4) / 100% = 45 g • 5% / 100% = 2.25 g.
The number of moles of sulfuric acid.
n (H2SO4) = m / Mr = 2.25 g / 98 g / mol = 0.02 mol.
The number of moles of the formed salt and acid will be equal.
n (H2SO4) = n (BaSO4) = 0.02 mol.
Mass of barium sulfate.
m (BaSO4) = n • Mr = 0.02 mol • 233.4 g / mol = 4.67 g.