What mass of quicklime and what volume of carbon dioxide can be extracted from 1 ton of limestone, impurities in which are 5%.

1) Determine the net mass. limestone: 5% – impurities, 95% – pure. CaCO3, m (CaCO3) = 0.95 * 1000 = 950 kg;
2) Calculate the amount of kmol CaCO3: M (CaCO3) = 100 g / mol (kg / kmol), n (CaCO3) = 950/100 = 9.5 kmol;
3) Determine the quantities of kmol CaO and CO2: n (CaO) = n (CO2) = n (CaCO3) = 9.5 kmol;
4) Calculate the mass of CaO: M (CaO) = 56 g / mol (kg / kmol), n (CaO) = 9.5 * 56 = 532 kg;
5) Calculate the volume of CO2 at standard conditions: Vm = 22.4 l / mol (m3 / kmol), V = 9.5 * 22.4 = 212.8 m3;
Answer: 532 kg CaO, 212.8 m3 CO2