What mass of salt and water is required to prepare 20 g of a 40% solution of aluminum chloride?

The mass of the solution is equal to – 20 g.

Mass fraction of the solution – 40%.

Determine the mass of the solution and the mass of water required to prepare the solution.

To solve, you need to use the following formula.

W = m r.v. / m r-ra * 100%.

First, let’s determine the mass of the salt.

m salt = 20 * 0.4 = 8 g.

It turns out that the mass of salt is 8 grams.

Next, we determine the mass of water.

m solution = m salt + m H2O.

m H2O = m solution – m r.v.

m H2O = 20 – 8 = 12 g.

It turns out that the mass of water is 12 grams.

Answer: the mass of salt is 8 g, the mass of water is 12 g.



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