What mass of salt and water should be taken to get 500 g of saline solution with w = 1%

Data: m – given mass of brine (m = 240 g); ωс – required mass fraction of salt (ωс = 1% = 0.01).

1) The required mass of salt: mс = m * ωс = 500 * 0.01 = 5 g.

2) The required mass of water: mH2O = m – mс = 500 – 0.01 = 495 g or mH2O = m * ωH2O = m * (1 – ωс) = 500 * (1 – 0.01) = 495 g.

Answer: To prepare the saline solution in question, you will need 5 g of salt and 495 g of water.