What mass of salt is formed after the reaction of copper (II) oxide weighing 8 g with hydrochloric acid?

Given:
m (CuO) = 8 g
To find:
m (salt) -?
Decision:
1) CuO + 2HCl => CuCl2 + H2O;
2) n (CuO) = m (CuO) / M (CuO) = 8/80 = 0.1 mol;
3) n (CuCl2) = n (CuO) = 0.1 mol;
4) m (CuCl2) = n (CuCl2) * M (CuCl2) = 0.1 * 135 = 13.5 g.
Answer: The mass of CuCl2 is 13.5 g.



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