What mass of salt is formed by the interaction of 400 g of a solution with a mass fraction of hydrochloric

| February 9, 2021 | education

What mass of salt is formed by the interaction of 400 g of a solution with a mass fraction of hydrochloric acid of 7.3% and aluminum hydroxide?

1. The interaction of hydrochloric acid and aluminum hydroxide describes the equation:

3HCl + Al (OH) 3 = AlCl3 + 3H2O;

2.Calculate the mass of hydrogen chloride:

m (HCl) = w (HCl) * m (solution) = 0.073 * 400 = 29.2 g;

3. calculate the chemical amount of hydrogen chloride:

n (HCl) = m (HCl): M (HCl) = 29.2: 36.5 = 0.8 mol;

4.According to the equation of aluminum chloride, the reaction produces three times less than hydrochloric acid reacts:

n (AlCl3) = n (HCl): 3 = 0.8: 3 = 0.2667 mol;

5. find the mass of the formed salt:

m (AlCl3) = n (AlCl3) * M (AlCl3);

M (AlCl3) = 27 + 35.5 * 3 = 133.5 g / mol;

m (AlCl3) = 0.2667 * 133.5 = 35.6 g.

Answer: 35.6 g.



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