What mass of salt is formed by the interaction of potassium oxide with 0.2L of carbon (IV) oxide?

univerkov | May 1, 2021 | education

1) Getting salt (calcium carbonate): CaCO3 = CaO + CO2.

2) The amount of CO2 substance: νСО2 = VСО2 / Vm, where VСО2 is the volume of reacted СО2 (VСО2 = 0.2 l); Vm – molar volume (Vm = 22.4 l / mol).

Calculation: νСО2 = VСО2 / Vm = 0.2 / 22.4 ≈ 0.00893 mol.

3) The ratio of the amount of substance: νСО2 / νСаСО3 = 1/1 = 1.

4) Molar mass of CaCO3: MСаСО3 = 40 * 1 (calcium) + 12 * 1 (carbon) + 16 * 3 (oxygen) = 100 g / mol.

5) The mass of the obtained CaCO3: m = νCaCO3 * MCaCO3 = 0.00893 * 100 = 0.893 g.

Answer: 0.893 g of calcium carbonate should have formed.

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