What mass of salt is formed by the interaction of sodium hydroxide with 46 g of sulfuric acid?

univerkov | December 30, 2020 | education

2NaOH + H2SO4 = Na2SO4 + 2H2O n (NaOH) = 46: 40 = 1.15 mol.
n (Na2SO4) = 1.15 * 1: 2 = 0.575.
m (Na2SO4) = 0. 575 * 142 = 81. 65g.
Answer: m (Na2SO4) = 81. 65 grams.

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