What mass of salt is formed if 80 g of sodium hydroxide act on 200 g of formic acid?

univerkov | September 19, 2021 | education

Data: m (HCOOH) = 200 g; m (NaOH) = 80 g.

1) The equation of the considered reaction: HCOOH (formic acid) + NaOH (sodium hydroxide) = НСООNa (obtained salt) + H2O (water).

2) Molar masses of substances: M (HCOOH) = 1 * 2 (hydrogen) + 12 * 1 (carbon) + 16 * 2 (oxygen) = 46 g / mol; M (NaOH) = 23 * 1 (sodium) + 16 * 1 (oxygen) + 1 * 1 (hydrogen) = 40 g / mol; M (НСООNa) = 1 * 1 (hydrogen) + 12 * 1 (carbon) + 16 * 2 (oxygen) + 23 * 1 (sodium) = 68 g / mol.

3) Amounts of substance:

ν (HCOOH) = 200 g / 46 g / mol ≈ 4.35 mol.

ν (NaOH) = 80 g / 40 g / mol = 2 mol.

Lack of sodium hydroxide.

4) Proportion: m (NaOH) / M (NaOH) = ν (1 mol) = m (НСООNa) / M (НСООNa).

m (НСООNa) = 80 * 68/40 = 136 g.

Answer: A salt with a mass of 136 g was formed.

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