What mass of salt is formed when magnesium oxide interacts with 100 g of a 6.3% nitric acid solution?

Given:
m solution (HNO3) = 100 g
w (HNO3) = 6.3% = 0.063
To find:
m (Mg (NO3) 2)
Decision:
MgO + 2HNO3 = H2O + Mg (NO3) 2
m in-islands (Mg (NO3) 2 = w * m solution = 0.063 * 100 g = 6.3 g
n (HNO3) = m / M = 6.3 g / 63 g / mol = 0.1 mol
n (HNO3): n (Mg (NO3) 2) = 2: 1
n (Mg (NO3) 2) = 0.1 mol / 2 = 0.05 mol
m (Mg (NO3) 2) = n * M = 0.05 mol * 148 g / mol = 7.4 g
Answer: 7.4 g