What mass of salt is obtained by the interaction of 162 grams of zinc oxide with sulfuric acid?

Zinc oxide reacts with sulfuric acid to form water and zinc sulfate. The reaction is described by the following equation:
ZnO + H2SO4 = ZnSO4 + H2O;
1 mole of oxide reacts with 1 mole of acid. This synthesizes 1 mol of salt and 1 mol of water.
Let’s calculate the amount of zinc oxide.
M ZnO = 65 + 16 = 81 grams / mol;
N ZnO = 162/81 = 2 mol;
During the reaction, 2 mol of zinc sulfate will be synthesized. Let’s calculate its weight.
M ZnSO4 = 65 + 32 + 16 x 4 = 161 grams / mol;
m ZnSO4 = 2 x 161 = 322 grams;