What mass of salt will be obtained if sulfuric acid reacts with 214 g of iron hydroxide?

univerkov | February 26, 2021 | education

Find the amount of iron (II) hydroxide substance.

n = m: M.

M (Fe (OH) 2) = 56+ 34 = 90 g / mol.

n = 214 g: 90 g / mol = 2.38 mol.

Let’s compose the reaction equation, find the quantitative ratios of substances.

Fe (OH) 2 + H2SO4 = FeSO4 + 2H2O.

For 1 mole of iron hydroxide there is 1 mole of salt. Substances are in quantitative ratios 1: 1. The amount of the substance will be the same.

n (Fe (OH) 2) = n (FeSO4) = 2.38 mol.

Let’s find the mass of salt.

m = n M.

M (FeSO4) = 56 + 32 + 64 = 152 g / mol.

m = 2.38 mol × 152 g / mol = 361.76 g.

Answer:; m = 361.76 g.

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