What mass of sand and cement is needed to prepare 10 kg of a mixture with a mass fraction of sand of 80%?
September 12, 2021 | education
| Given:
m mixture = 10 kg
ω (sand) = 80%
Find:
m (sand) -?
m (cement) -?
1) m (sand) = ω (sand) * m mixture / 100% = 80% * 10/100% = 8 kg;
2) m (cement) = m mixture – m (sand) = 10 – 8 = 2 kg.
Answer: The mass of sand is 8 kg; cement – 2 kg.
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