What mass of sand containing 85% SiO₂ is required to obtain sodium silicate weighing 50 g?
| February 13, 2021 | education
The equation for obtaining sodium silicate:
SiO2 + 2NaOH = Na2SiO3 + H2O.
We find the number of moles of the formed sodium silicate:
n (Na2SiO3) = m (Na2SiO3): M (Na2SiO3) = 50: 122 = 0.41 mol.
Accordingly, n (Na2SiO3) = n (SiO2).
Knowing the number of moles, we calculate the mass of silicon dioxide:
m (SiO2) = n * Mr / W = 0.41 * 60: 85% = 29 g.
One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.
