What mass of sediment can be obtained by the interaction of magnesium chloride with a mass of 5.7 g with potassium phosphate?
| December 1, 2020 | education
Given: m (MgCl2) = 5.7 g.
Find: m (Mg3 (PO4) 2) -?
Solution: 0.06 mol x 3MgCl2 + 2K3PO4> Mg3 (PO4) 2 = Mg3 (PO4) + 3 mol 1 mol + 6KCl 1) n (MgCl2) = 5.7: (35.5 * 2 + 24) = 0 , 06 (mol) 2) xn (Mg3 (PO4) 2) = (0.06 * 1): 3 = 0.02 (mol) 3) m (Mg3 (PO4) 2) = 0.02 * (16 * 8 + 31 * 2 + 24 * 3) = 5.24 (g)
Answer: m (Mg3 (PO4) 2) = 5.24 (g)
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