What mass of silane SiH4 is formed by the interaction of 76 g of magnesium silicide Mg2Si

| August 22, 2021 | education

What mass of silane SiH4 is formed by the interaction of 76 g of magnesium silicide Mg2Si with a solution containing 91.25 g of hydrogen chloride?

1. Let us write down the equation of the reaction reflecting the interaction of magnesium silicide with hydrogen chloride:

Mg2Si + 4HCl = 2MgCl2 + SiH4;

2. Let’s calculate the chemical quantities of the starting materials:

n (Mg2Si) = m (Mg2Si): M (Mg2Si);

M (Mg2Si) = 2 * 24 + 28 = 76 g / mol;

n (Mg2Si) = 76: 76 = 1 mol;

n (HCl) = m (HCl): M (HCl) = 91.25: 36.5 = 2.5 mol;

3. The lack of hydrogen chloride is taken, according to its data, we determine the amount of silane obtained:

n (SiH4) = n (HCl): 4 = 2.5: 4 = 0.625 mol;

4. Let’s calculate the mass of silane:

m (SiH4) = n (SiH4) * M (SiH4);

M (SiH4) = 28 + 4 = 32 g / mol;

m (SiH4) = 0.625 * 32 = 20 g.

Answer: 20 g.



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