What mass of silicon is required to interact with 320 g of a solution with a mass fraction of sodium hydroxide of 15%?

univerkov | December 8, 2020 | education

2NaOH + Si + H2O = Na2SiO3 + 2H2
m (NaOH) h = 320 * 0.15 = 48 grams
n (NaOH) = 48/40 = 1.2 mol
n (Si) = 1.2 / 2 = 0.6 mol
m (Si) = 28 * 0.6 = 16.8 grams

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