What mass of silver can be displaced by copper from a solution of silver nitrate weighing 340 g

What mass of silver can be displaced by copper from a solution of silver nitrate weighing 340 g with a mass fraction of salt of 2%?

Find the mass of AgNO3 in solution.

W = m (substance): m (solution) × 100%,

hence m (substance) = (m (solution) × w): 100%.

m (substance) = (340 g × 2%): 100% = 6.8 g.

Let’s find the amount of AgNO3.

n = m: M.

M (AgNO3) = 170 g / mol.

n = 6.8 g: 170 g / mol = 0.04 mol.

Let’s find the quantitative ratios of substances.

Cu + 2 AgNO3 = Cu (NO3) 2 + 2Ag ↓.

There are 2 mol of Ag per 2 mol of AgNO3.

Substances are in quantitative ratios 1: 1.

The amount of substance will be the same.

n (Ag) = n (AgNO3) = 0.04 mol.

Find the mass Ag

M (Ag) = 108 g / mol.

m = n × M.

m = 108 g / mol × 0.04 mol = 4.32 g.

Answer: 4.32 g.