What mass of silver can be displaced by copper from a solution of silver nitrate weighing 340 g
May 20, 2021 | education
| What mass of silver can be displaced by copper from a solution of silver nitrate weighing 340 g with a mass fraction of salt of 2%?
Find the mass of AgNO3 in solution.
W = m (substance): m (solution) × 100%,
hence m (substance) = (m (solution) × w): 100%.
m (substance) = (340 g × 2%): 100% = 6.8 g.
Let’s find the amount of AgNO3.
n = m: M.
M (AgNO3) = 170 g / mol.
n = 6.8 g: 170 g / mol = 0.04 mol.
Let’s find the quantitative ratios of substances.
Cu + 2 AgNO3 = Cu (NO3) 2 + 2Ag ↓.
There are 2 mol of Ag per 2 mol of AgNO3.
Substances are in quantitative ratios 1: 1.
The amount of substance will be the same.
n (Ag) = n (AgNO3) = 0.04 mol.
Find the mass Ag
M (Ag) = 108 g / mol.
m = n × M.
m = 108 g / mol × 0.04 mol = 4.32 g.
Answer: 4.32 g.
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