What mass of silver chloride is formed by the action of 17 g of silver nitrate on a calcium chloride solution?

1. Let’s compose the equation of interaction between calcium chloride and silver nitrate:

CaCl2 + 2AgNO3 = 2AgCl ↓ + Ca (NO3) 2;

2. Calculate the chemical amount of silver nitrate:

n (AgNO3) = m (AgNO3): M (AgNO3);

M (AgNO3) = 108 + 14 + 3 * 16 = 170 g / mol;

n (AgNO3) = 17: 170 = 0.1 mol;

3. Determine the amount of the formed silver chloride:

n (AgCl) = n (AgNO3) = 0.1 mol;

4. Find the mass of the sediment:

m (AgCl) = n (AgCl) * M (AgCl);

M (AgCl) = 108 + 35.5 = 143.5 g / mol;

m (AgCl) = 0.1 * 143.5 = 14.35 g.

Answer: 14.35 g.