What mass of silver chloride is formed by the action of a solution of magnesium chloride with silver nitrate weighing 34 grams?

univerkov | January 17, 2021 | education

Given:
m (AgNO3) = 34 g
To find:
m (AgCl)
Decision:
MgCl2 + 2AgNO3 = 2AgCl + Mg (NO3) 2
n (AgNO3) = 34 g: 170 g / mol = 0.2 mol
n (AgNO3): n (AgCl) = 2: 2
n (AgCl) = 0.2 mol
m (AgCl) = 0.2 mol * 143.5 g / mol = 28.7 g
Answer: 28.7 g

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