What mass of silver is formed in the reaction of 4.4 g of acetaldehyde with an ammoniacal solution of silver oxide?

Let’s execute the solution:
1. By condition, we write down the equation of the process:
m = 4.4 g. X g. -?
СН3СОН + Ag2O = CH3COOH + 2Ag – oxidation of ethanal, reaction of a silver mirror, silver is released, acetic acid;
2. Let’s make calculations using the formulas:
M (C2H4O) = 44 g / mol.
M (Ag) = 107.8 g / mol.
Y (C2H4O) = m / M = 4.4 / 44 = 0.1 mol.
3. Proportion:
0.1 mol (C2H4O) – X mol (Ag);
-1 mol -2 mol from here, X mol (Ag) = 0.1 * 2/1 = 0.2 mol.
4. Find the mass of the product:
m (Ag) = Y * M = 0.2 * 107.8 = 21.56 g.
Answer: Silver was obtained with a mass of 21.56 g.