What mass of sodium carbonate is formed by the interaction of 40 g of sodium oxide with carbon dioxide?

The reaction of sodium oxide with carbon dioxide is described by the following chemical reaction equation:

2Na2O + CO2 = Na2CO3;

From 2 moles of sodium oxide, 1 mole of sodium carbonate is synthesized.

Let’s calculate the available chemical amount of sodium oxide substance.

M Na2O = 23 x 2 + 16 = 62 grams / mol;

N Na2O = 40/62 = 0.645 mol;

From this amount of oxide, it is possible to synthesize 0.645 / 2 = 0.323 mol of sodium soda.

Let’s calculate its weight. To do this, we multiply the amount of the substance by its molar mass.

M Na2CO3 = 23 x 2 + 12 + 16 x 3 = 106 grams / mol;

m Na2CO3 = 0.323 x 106 = 34.24 grams;