What mass of sodium carbonate is obtained from 224 liters of carbon monoxide (IV)?

Given:
V (CO2) = 224 l.
interaction of NaOH with CO2;
Find: m (Na2CO3) -?
Decision:
1) Let’s write the reaction equation:
2NaOH + CO2 = Na2CO3 + H2O
From the reaction – 1 mol of Na2CO3 is consumed per 1 mol of CO2;
2) Find v (CO2), v (CO2) = V / Vm, v (CO2) = 224 l / 22.4 l / mol = 10 mol.
Since v (CO2): v (Na2CO3) = 1: 1, then v (Na2CO3) = v (CO2) = 10 mol;
3) 4) M (Na2CO3) = 23 * 2 + 12 + 16 * 3 = 46 + 12 + 48 = 106 g / mol.
m (Na2CO3) = 106 g / mol * 10 mol = 1060 g.
Answer: From 224 liters of CO2 gas, 1060 grams of Na2CO3 is formed.