What mass of sodium chloride is formed when 16 g of sodium hydroxide is neutralized with an excess of hydrochloric acid?

The equation for the reaction of sodium hydroxide with hydrochloric acid:

NaOH + HCl = NaCl + H2O

The amount of NaOH substance:

v (NaOH) = m (NaOH) / M (NaOH) = 16/40 = 0.4 (mol).

According to the reaction equation, 1 mol of NaCl is formed from 1 mol of NaOH, therefore:

v (NaCl) = v (NaOH) = 0.4 (mol).

Thus, the mass of the formed sodium chloride:

m (NaCl) = v (NaCl) * M (NaCl) = 0.4 * 58.5 = 23.4 (g).

Answer: 23.4 g.

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