What mass of sodium has reacted with water if it is known that hydrogen has evolved and 40 g of NaOH has been formed.

1. Let’s make the equation of the ongoing chemical reaction.
2Na + 2H2O = 2NaOH + H2.
2. Find the amount of sodium hydroxide formed.
n (NaOH) = m (NaOH) / M (NaOH) = 40 g / 40 g / mol = 1 mol.
3. Using the reaction equation, we calculate the mass of sodium.
n (Na) = n (NaOH) = 1 mol.
m (Na) = n (Na) * M (Na) = 1 mol * 23 g / mol = 23 g.
Answer: m (Na) = 23 g.



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