What mass of sodium hydroxide and water is required to prepare 80 g of its 40% solution?

In order to find the mass of sodium hydroxide, it is necessary to multiply its mass fraction by the mass of the solution:

m NaOH = 80 x 0.4 = 32 grams;

To find the mass of water, subtract the mass of sodium hydroxide from the mass of the solution:

m H2O = 80 – 32 = 48 grams;

Check: 32 + 48 = 80 grams;



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