What mass of sodium hydroxide can react with sulfuric acid weighing 4.6 g?

2NaOH + H2SO4 = Na2SO4 + 2H2O.
1) According to the periodic table, we determine the molar mass of sulfuric acid: 1 * 2 + 32 + 16 * 4 = 98.
2) Find the amount of sulfuric acid substance. To do this, divide the mass of the acid by its molar mass: 4.6 / 98 = 0.05 mol.
3) According to the reaction equation, there are two moles of sodium hydroxide per mole of sulfuric acid. This means that the amount of sodium hydroxide substance is: 0.05 / 2 = 0.025 mol.
4) Molar mass of sodium hydroxide: 23 + 1 + 16 = 40.
5) Mass of sodium hydroxide: 40 * 0.025 = 1 g – answer.



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