What mass of sodium hydroxide is formed by the interaction of 2.3 g of sodium with water?

Let’s write the reaction equation:

2Na + 2H2O = 2NaOH + H2 ↑

Let’s find the amount of sodium substance:

v (Na) = m (Na) / M (Na) = 2.3 / 23 = 0.1 (mol).

According to the reaction equation, from 2 mol of Na, 2 mol of NaOH is formed, therefore:

v (NaOH) = v (Na) = 0.1 (mol).

Thus, the mass of the resulting sodium hydroxide is:

m (NaOH) = v (NaOH) * M (NaOH) = 0.1 * 40 = 4 (g).

Answer: 4 y.