What mass of sodium hydroxide is needed to neutralize 12.6 g. nitric acid?
| February 24, 2021 | education
1. Let’s write the reaction equation:
NaOH + HNO3 = NaNO3 + H2O.
2. Find the amount of nitric acid:
n (HNO3) = m (HNO3) / M (HNO3) = 12.6 g / 63 g / mol = 0.2 mol.
3. Using the reaction equation, we find the amount of sodium hydroxide, and then its mass:
n (NaOH) = n (HNO3) = 0.2 mol.
m (NaOH) = n (NaOH) * M (NaOH) = 0.2 mol * 40 g / mol = 8 g.
Answer: m (NaOH) = 8 g.
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