What mass of sodium hydroxide is required to completely neutralize 180 g of 35% acetic acid solution?

1. Let’s write down the reaction equation:

NaOH + CH3COOH = CH3COONa + H2O.

2. Find the mass, and then the amount of acetic acid:

m (CH3COOH) = (m (solution) * ω (CH3COOH)) / 100% = 180 g * 35% / 100% = 63 g.

n (CH3COOH) = m (CH3COOH) / M (CH3COOH) = 63 g / 60 g / mol = 1.05 mol.

3. Using the reaction equation, we find the amount and then the mass of sodium hydroxide:

n (NaOH) = n (CH3COOH) = 1.05 mol.

m (NaOH) = n (NaOH) * M (NaOH) = 1.05 mol * 40 g / mol = 42 g.

Answer: m (NaOH) = 42 g.