What mass of sodium hydroxide will react with 200 g of nitric acid solution, in which the mass

What mass of sodium hydroxide will react with 200 g of nitric acid solution, in which the mass fraction of acid is 12.6%?

1. Let’s write down the reaction equation:

NaOH + HNO3 = NaNO3 + H2O.

2. Find the mass, and then the amount of nitric acid:

m (HNO3) = (m (solution) * ω (HNO3)) / 100% = 200 g * 12.6% / 100% = 25.2 g.

n (HNO3) = m (HNO3) / M (HNO3) = 25.2 g / 63 g / mol = 0.4 mol.

3. According to the Reaction Equation, we find the amount of sodium hydroxide, and then its amount:

n (NaOH) = n (HNO3) = 0.4 mol.

m (NaOH) = n (NaOH) * M (NaOH) = 0.4 mol * 40 g / mol = 16 g.

Answer: m (NaOH) = 16 g.