What mass of sodium nitrate is formed by the interaction of 5.2 g of nitric acid with sodium hydroxide?
| May 3, 2021 | education
HNO3 + NaOH = NaNO3 + H2O.
1) Find the molar mass of nitric acid according to the periodic table: 1 + 14 + 48 = 63.
2) Find the amount of nitric acid by dividing the mass of nitric acid by its molar mass: 5.2 / 63 = 0.08 mol.
3) According to the reaction equation, there is one mole of sodium nitrate for one mole of nitric acid. This means that the amount of sodium nitrate substance is 0.08 mol.
4) Molar mass of sodium nitrate: 23 + 14 + 3 * 16 = 85.
5) Find the mass of sodium nitrate. To do this, we multiply the molar mass by the amount of nitrate substance: 0.08 * 85 = 6.8 g – the answer.
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