What mass of sodium oxide is required to interact with sulfuric acid weighing 12.25 g.

1. We write down the equation of interaction of sodium oxide with sulfuric acid:
Na2O + H2SO4 = Na2SO4 + H2O;
2.calculate the chemical amount of sulfuric acid:
n (H2SO4) = m (H2SO4): M (H2SO4);
M (H2SO4) = 2 + 32 + 4 * 16 = 98 g / mol;
n (H2SO4) = 12.25: 98 = 0.125 mol;
3.the amounts of reactants according to the reaction equation are the same:
n (Na2O) = n (H2SO4) = 0.125 mol;
4.Find the mass of sodium oxide required for the reaction:
m (Na2O) = n (Na2O) * M (Na2O);
M (Na2O) = 23 * 2 + 16 = 62 g / mol;
m (Na2O) = 0.125 * 62 = 7.75 g.
Answer: 7.75 g.