What mass of sodium should be taken to prepare an aqueous solution of sodium hydroxide weighing 80 g
What mass of sodium should be taken to prepare an aqueous solution of sodium hydroxide weighing 80 g with a mass fraction of 10%?
1.Let’s find the mass of sodium hydroxide in the solution:
W = m (substance): m (solution) × 100%.
m (substance) = w × m (solution): 100%.
m (NaOH) = (10% × 80 g): 100% = 8 g.
2.Let’s find the amount of sodium hydroxide substance.
n = m: M,
M (NaOH) = 23 + 16 + 1 = 40 g / mol.
n = 8 g: 40 g / mol = 0.2 mol.
3. Let’s compose the reaction equation.
2 Na + 2H2O = 2NaOH + H2.
According to the reaction equation, 2 mol of sodium accounts for 2 mol of sodium hydroxide, that is, they are in quantitative ratios of 1: 1. The amounts of substances of these substances will be the same.
4. Find the mass of sodium.
m (Na) = n × M,
n (Na) = 0.2 mol.
M (Na) = 23g / mol.
m (Na) = 0.2 mol × 23 mol = 4.6 g.
Answer: 4.6 g.