What mass of sodium silicate is formed by fusing sodium hydroxide with 50 g of silicon oxide containing 10% impurities?

The reaction for producing sodium silicate from silicon oxide and sodium hydroxide is described by the following chemical equation:

2NaOH + SiO2 = Na2SiO3 + H2O;

Determine the chemical amount of silicon oxide:

For this purpose, we divide its weight by the mass of 1 mole of the substance.

M SiO2 = 28 + 16 x 2 = 60 grams / mol;

N SiO2 = 50 x 0.9 / 60 = 0.75 mol;

An equivalent amount of sodium silicate can be synthesized.

Let’s calculate its weight.

To do this, multiply the amount of the substance by its molar weight.

M Na2SiO3 = 23 x 2 + 28 + 16 x 3 = 122 grams / mol;

m Na2SiO3 = 0.75 x 122 = 91.5 grams;