What mass of sodium sulfate will be obtained by the interaction of 150 g of sodium hydroxide containing 20% impurities
| December 10, 2020 | education
What mass of sodium sulfate will be obtained by the interaction of 150 g of sodium hydroxide containing 20% impurities with 250 g of 60% sulfuric acid solution. The reaction product yield was 90%.
2NaOH + H2SO4 = Na2SO4 + 2H2O
n (NaOH) = (150 * 0.8): 40 = 3 moles
n (H2SO4) = (250 * 0.6): 98 = 1.53 mol
hence acid is in excess
n (Na2SO4) = 1.5 MOL
m theor (Na2SO4) = 1.5 * 142 = 213 gr
m practical (Na2SO4) = 213 * 0.9 = 191.7
answer 191.7
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