What mass of sulfate acid should be taken to neutralize 8 grams of sodium hydroxide?

univerkov | March 31, 2021 | education

1. Let’s write down the reaction equation:

2NaOH + H2SO4 = Na2SO4 = 2H2O.

2. Find the amount of sodium hydroxide:

n (NaOH) = m (NaOH) / M (NaOH) = 8 g / 40 g / mol = 0.2 mol.

3. According to the reaction equation, we find the amount and then the mass of sulfuric acid:

n (H2SO4) = 0.5n (NaOH) = 0.1 mol.

m (H2SO4) = n (H2SO4) * M (H2SO4) = 0.1 mol * 98 g / mol = 9.8 g.

Answer: m (H2SO4) = 9.8 g.

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