What mass of sulfur was burned if the result was SO2 with an amount of 4.3 mol? Product yield 80%
| May 7, 2021 | education
1. Let’s write down the reaction equation:
S + O2 = SO2.
2. Find the theoretical yield of sulfur dioxide:
ntheor (SO2) = nprak (SO2) * 100% / η (SO2) = 4.3 mol * 100% / 80% = 5.375 mol.
3. Using the equation, we find the amount, and then the mass of sulfur:
n (S) = ntheor (SO2) = 5.375 mol.
m (S) = n (S) * M (S) = 5.375 mol * 32 g / mol = 172 g.
Answer: m (S) = 172 g.
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