What mass of sulfuric acid is formed by the interaction of 16 g of sulfur oxide (6) with water? how much will react?

Reaction equation: SO3 + H2O = H2SO4
According to the periodic table, we determine the molar mass of the oxide: M = 32 + 16 * 3 = 80 g / mol. The molar mass of sulfuric acid: M = 1 * 2 + 32 + 16 * 4 = 98 g / mol.
Find the amount of oxide: n = m / M = 16 g / 80 g / mol = 0.2 mol.
According to the equation, 1 mol of oxide forms 1 mol of acid, which means n (SO3) = n (H2SO4) = 0.2 mol.
Find the mass of sulfuric acid: m = n * M = 0.2 mol * 98 g / mol = 19.6 g.
Answer: 19.6 g of acid are formed, 0.2 mol of oxide will react.