What mass of sulfuric acid is required to interact with 112 g of calcium oxide?

Let’s implement the solution:
1. In accordance with the condition of the problem, we write down the process:
X g -? m = 112 g.
H2SO4 + CaO = CaSO4 + H2O – ion exchange, obtained calcium sulfate in the sediment;
2. Calculations by formulas:
M (H2SO4) = 98 g / mol.
M (CaO) = 56 g / mol.
3. Determine the amount of the original substance, if the mass is known:
Y (CaO) = m / M = 112/56 = 2 mol.
Y (H2SO4) = 2 mol since the amount of substances is 1 mol.
4. Find the mass of acid:
m (H2SO4) = Y * M = 2 * 98 = 196 g.
Answer: the mass of sulfuric acid is 196 g.