What mass of the ether can be obtained in the esterification reaction between acetic acid weighing 12 g

| June 28, 2021 | education

What mass of the ether can be obtained in the esterification reaction between acetic acid weighing 12 g and butanol weighing 14.8 g.

Find the amount of acetic acid substance by the formula:

N = M: M.

M (CH3COH) = 60 g / mol.

n = 12 g: 60 g / mol = 0.2 mol.

Find the amount of substance of butanol.

M (C4N9on) = 12 × 4 + 10 + 16 = 74 g / mol.

N = 14.8 g: 74 g / mol = 0.2 mol.

Substances are in the same quantity.

We will make the reaction equation, we will find the quantitative ratios of substances.

C4N9on + CH3COH → CH3COOS4N9 + H2O.

According to the reaction equation to 1 mol, acid accounted for 1 mol ether. Substances are in quantitative ratios 1: 1.

The amount of substance will be the same.

N (CH3COH) = N (CH3COOS4N9) = 0.2 mol.

We find a mass of ether by the formula:

m = n × m,

M (CH3COOS4N9) = 116 g / mol.

m = 0.2 mol × 116 g / mol = 23.2 g

Answer: 23.2 g



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