What mass of tungsten can be obtained by hydrogen reduction of an ore weighing 145 grams

| June 1, 2021 | education

What mass of tungsten can be obtained by hydrogen reduction of an ore weighing 145 grams, containing tungsten (VI) oxide and non-reducing impurities, the mass fraction of which is 20%?

The reduction of tungsten from its oxide (VI) with hydrogen proceeds at a high temperature. The reaction produces pure tungsten metal and water. Reaction equation:

WO3 + 3 H2 = W + 3 H2O

To solve the problem, let us find the mass of pure tungsten (VI) oxide in the sample. Its concentration in the ore: 100% – 20% = 80%

m = 145 * 80/100 = 116 g.

The molar mass of tungsten is 184 g / mol, the molar mass of WO3 = 232 g / mol

Now, using the reaction equation, we calculate the mass of tungsten reduced from ore. Let’s make the proportion:

116 g of tungsten oxide corresponds to X g of tungsten, as

232 g / mol of tungsten oxide corresponds to 184 g / mol.

X = (116 * 184) / 232 = 92 g of tungsten

Answer: 92 g of tungsten



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