What mass of water enters into a hydrolysis reaction with sucrose weighing 68.4 g?

In accordance with the condition of the problem, we compose the reaction equation:
C12H22O11 + H2O = C6H12O6 (glucose) + C6H12O6 (sucrose) – the reaction of hydrolysis of sucrose, glucose and sucrose are formed;
Let’s calculate the molar masses of substances;
M (C12H22O11) = 12 * 12 + 1 * 22 + 16 * 11 = 342 g / mol;
M (H2O) = 1 * 2 + 16 = 18 g / mol;
Determine the amount of mol of sucrose by the formula:
Y (C12H22O11) = m / M = 68.4 / 342 = 0.2 mol;
Let’s make the proportion:
0.2 mol (C12H22O11) – X mol (H2O);
-1 mol – 1 mol from here, X mol (H2O) = 0.2 * 1/1 = 0.2 mol;
Let’s calculate the mass of water by the formula:
m (H2O) = Y * M = 0.2 * 18 = 3.6 g.
Answer: 3.6 g of water is required to carry out the reaction.