What mass of water is formed by the interaction of 100 g of h2so4 with alkali NaOh?

The reaction equation between hydrochloric acid and sodium hydroxide looks like this:

H2SO4 + 2 NaOH = Na2SO4 + 2 H2O

Molar mass of sulfuric acid = 98 g / mol; molar mass of water = 18 g / mol.

According to the reaction equation, we make up the proportion:

X g of water corresponds to 100 g of sulfuric acid as

2 * 18 g / mol corresponds to 98 g / mol

X = 100 * 2 * 18/98 = 36.73 g of water

Answer: 36.73 g of water.



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