What mass of water is formed by the interaction of phosphoric acid with potassium hydroxide weighing 48.72

The equation of the ongoing reaction: H3PO4 + 3KOH = K3PO4 + 3H2O.
1) According to the periodic table, we determine the molar mass of potassium hydroxide: 39 + 16 + 1 = 56.
2) Find the amount of potassium hydroxide substance. To do this, divide the mass of the hydroxide by its molar mass: 48.72 / 56 = 0.87 mol.
3) According to the reaction equation, three moles of potassium hydroxide account for three moles of water. This means that the amount of water substance is 0.87 mol.
4) Molar mass of water: 1 * 2 + 16 = 18.
5) Find the mass of water: 18 * 0.87 = 15.66 g – the answer.